Voltage drop between two points

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SUMMARY

The voltage drop between points A and B in a circuit can be calculated using Kirchhoff's Voltage Law (KVL) and Ohm's Law (V = IR). The current flowing through the circuit is determined by the equation ##\frac{E_2-E_1}{R_1+R_2+R_3+R_4}##, where E2 is greater than E1. To find the voltage drop specifically between points A and B, one must consider the resistors in the path; the correct approach is to sum the resistances of R1 and R2, as they are in series along the path from A to B.

PREREQUISITES
  • Understanding of Kirchhoff's Voltage Law (KVL)
  • Knowledge of Ohm's Law (V = IR)
  • Familiarity with series and parallel resistor configurations
  • Basic circuit analysis skills
NEXT STEPS
  • Study Kirchhoff's Voltage Law in-depth
  • Learn about series and parallel resistor combinations
  • Practice circuit analysis problems involving multiple resistors
  • Explore advanced topics in electrical circuits, such as Thevenin's and Norton's theorems
USEFUL FOR

Students studying electrical engineering, circuit designers, and anyone involved in analyzing or designing electrical circuits will benefit from this discussion.

terryds
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Homework Statement


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The question is: What's the voltage drop between point A and B ?? (Suppose that E2 > E1)2. The attempt at a solution

First, I need to solve the current flowing in this circuit, which can be done using KVL.
The current flowing is ##\frac{E_2-E_1}{R_1+R_2+R_3+R_4}## (which is clockwise in direction because E2 is bigger than E1)

But,I get confused in determining voltage drop between point A and B
I know that the formula is V = IR
But, I'm confused about the value of the resistor..

Is it R1 + R2 (since from point A to B the current flows from R1 to R2) ?
Or, should the resistor be the parallel series of R1-R2 and R3-R4 that makes an imaginary bridge between A and B ??
 
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terryds said:
But,I get confused in determining voltage drop between point A and B
I know that the formula is V = IR
But, I'm confused about the value of the resistor..

Is it R1 + R2 (since from point A to B the current flows from R1 to R2) ?
Or, should the resistor be the parallel series of R1-R2 and R3-R4 that makes an imaginary bridge between A and B ??
Your first thought was correct. You determine the potential between two points by taking a "KVL walk" along a path that leads from one point to the other.

You could also have gone the other way around the loop (counterclockwise) from A to B, summing the potential changes along the way. In that case you would be "walking" against the current, so you'd see potential rises as you cross the resistors rather than drops.
 
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