Is voltage the same in parallel circuits with different resistance values?

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In parallel circuits, the voltage across each branch remains constant and equal, regardless of the resistance values of the resistors. This means that Vt = V1 = V2 = V3 holds true for all resistors in parallel, not just those with the same resistance. The confusion arises from the fact that while the voltage is the same, the current varies based on the resistance, as described by Ohm's law (V = IR). Therefore, using resistors with different values does not change the voltage across them, but it does affect the current flowing through each resistor. Understanding this distinction is crucial for analyzing parallel circuits effectively.
Daniel2244
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Homework Statement


I have to write about voltage within a parallel circuit and the formula for voltage in parallel is Vt=V1=V2=V3. But I was wondering if that's only the case if the resistors have the same resistance becasue I used resistors with different values

Homework Equations


V1=V2=V3

The Attempt at a Solution


The answer is yes the voltage across each branch is the same only when the resistors are the same value. Becasue when you use resistors with higher/lower resistance the current flow is different. (higher Ω Lower I) so using Ohm's law V=IR the voltage will be different if resistors with different values are used in parallel.
 
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Daniel2244 said:

Homework Statement


I have to write about voltage within a parallel circuit and the formula for voltage in parallel is V1=V2=V3. But I was wondering if that's only the case if the resistors have the same resistance becasue I used resistors with different values

Homework Equations


V1=V2=V3

The Attempt at a Solution


The answer is yes the voltage across each branch is the same only when the resistors are the same value. Becasue when you use resistors with higher/lower resistance the current flow is different. (higher Ω Lower I) so using Ohm's law V=IR the voltage will be different if resistors with different values are used in parallel.
This is completely incorrect. See if you can figure out why
 
phinds said:
This is completely incorrect. See if you can figure out why
WOW!. My bad, I calculates something wrong. Vt=V1=V2=Vn...
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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