Is x=0 the Only Solution If x Is Less Than Every Positive Real Number n?

[transgalactic]

i got a real number called "x"

prove that if it follows this rule n>x>=0

for every real and positive "n"

then "x" must have the value x=0

??

 

[Office_Shredder]

What do you think? Consider if x is non-zero... what can you say then?

 

[transgalactic]

if x is non zero then "n" is non zero too

what is the next step

??

 

[Mark44]

Office Shredder is suggesting a proof by contradiction. Your next step is to think about what you need to do to carry out this proof. This is simple enough that you shouldn't have to ask for guidance at each and every step.

 

[transgalactic]

but from this expression
n>x>=0

"x" must not be equaled to 0

i can't see the way to solve it

??

 

[transgalactic]

They´re telling me that a positive real number x is smaller than ANY positive real number n. So n "pushes" x to the 0.

how to say that in math