Is Your Solution to the Limit Problem Correct?

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SUMMARY

The limit of the expression lim_{x->\infty}\frac{3x-cosx}{4x+sinx} evaluates to 0.75. The correct approach involves simplifying the expression by dividing both the numerator and denominator by x, leading to lim_{x->\infty}\frac{3-0}{4-0}=0.75. It is crucial to remove the limit operator from the final expression after evaluating the limit, as it is no longer necessary.

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[tex] lim_{x->\infty}\frac{3x-cosx}{4x+sinx}=lim_{x->\infty}\frac{\frac{3x-cosx}{x}}{\frac{4x+sinx}{x}}=lim_{x->\infty}\frac{3-0}{4-0}=0.75 [/tex]

i thought bounded/infinity=0


??
 
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You have the correct limit, but you should remove the limit operator from the expression below, since you have already "passed to the limit" in the previous expression:
[tex]lim_{x->\infty}\frac{3-0}{4-0}=0.75[/tex]
 
thanks
 

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