Is z^2 a Constant When Differentiating cos(yz^2) with Respect to y?

[JamesGoh]

To differentiate $cos(yz^{2})$ with respect to y


can we simply ignore the $z^{2}$ term in the differentiation ?

 

[Pythagorean]

yup! since it's with respect to y, z is irrelevant.

 

[HallsofIvy]

Do not "ignore" it, treat it like a constant!

 

[oferon]

treat it like a=z^2.. It's a constant when differentiating with respect to y