- #1

davedave

- 50

- 0

car A

let x = the current position of car A

speed = 72.2 km/h

time = x/72.2 hours

car B

let x + 48 = the current position of car B

speed = 53 km/h

time = (x + 48)/53 hours

so, both cars will have traveled for the same amount of time when car A catches up with car B.

then, x/72.2 = (x + 48)/53

solving for x gives x = -180.5 km

thus, time of car A is -2.5 hours.

You cannot have negative time.

Could someone explain my solution? Thanks.