Iteration/Root finding algorithm

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The discussion revolves around solving a homework problem related to an iteration/root-finding algorithm. The user successfully factorized a cubic equation for part a) but struggles with part b), particularly in demonstrating the uniqueness of the solution. It is clarified that while there are three complex solutions, the task is to show that the limit of the sequence converges to a specific value, cbrt(λ). The recursion equation provided is x_{n+1}= 2x_n/3 + λ/(3x_n^2), and users are encouraged to take limits to find the solution. The conversation emphasizes understanding the convergence and uniqueness of the limit rather than the existence of multiple solutions.
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Homework Statement



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The Attempt at a Solution



I've managed to do part a), by factorising the cubic you get when you rearrange the terms. I'm mostly stumped for part b). I know the sequence has to be contractive, otherwise it wouldn't converge. Also, how do I show it's the only solution? Thank you very much!
 
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I'm not sure what you mean by "show it's the only solution". There are, in fact, three (complex) solutions to the equation. What you are asked to do is show that the limit (which, assuming the sequence converges, is unique) does, in fact, satisfy the given equation, not that it is the "only" solution.

Your recursion equation is x_{n+1}= 2x_n/3+ \lambda/(3x_n^2). Take the limit of both sides as n goes to infinity and you have x= 2x/3+ \lambda/3x^2, where x= \lim_{n\to\infty} x_n. Multiply both sides of that by 3x^2.
 
Sorry, I meant how to show that the only possible value for limn→∞xn is cbrt(λ)! Also, if you could explain how to solve ii) of b) that would be great!
 
Bump: Any ideas about b) are welcome.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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