Jacobi Iteration Homework: Solving System of Equations

  • Thread starter Thread starter gtfitzpatrick
  • Start date Start date
  • Tags Tags
    Jacobi
Click For Summary
SUMMARY

The discussion focuses on solving a system of equations using the Jacobi Iteration method. The exact solution is determined to be x1 = 3 and x2 = 5. The matrix satisfies the condition for Jacobi iteration as the off-diagonal elements are less than the diagonal elements. The iterative calculations yield x(1) = (18/8, 14/4) and x(2) = (18/8, 71/16). To achieve an error within 0.001, participants are advised to use the a priori error expression rather than continuing iterations indefinitely.

PREREQUISITES
  • Understanding of linear algebra concepts, particularly systems of equations.
  • Familiarity with the Jacobi Iteration method for numerical solutions.
  • Knowledge of error analysis in iterative methods.
  • Basic proficiency in matrix operations and properties.
NEXT STEPS
  • Study the derivation and application of the Jacobi Iteration method.
  • Learn about a priori error estimates in iterative methods.
  • Explore convergence criteria for iterative methods in linear algebra.
  • Practice solving systems of equations using numerical methods in MATLAB or Python.
USEFUL FOR

Students in numerical analysis, mathematicians, and engineers who are working with iterative methods for solving systems of equations.

gtfitzpatrick
Messages
372
Reaction score
0

Homework Statement



consider the systems of equations
2x1 - x2 = 1
-31 + 4x2 =11

a) determine the ixact solution?

b)apply jacobi iteration.Does the matrix C satisfy the required condition?

c)starting with x(0) =( \stackrel{1}{1} ) calculate x(1) and x(2) and the prior error bound for x(2)

d)how many iterations will suffice to get within 0.001 of the solution?

a) grand 3 and 5
b) it clearly satisfies the condition as off diagonals < diagonals
c) so did it out got
x(0) = ( \stackrel{1}{14/4} )

x(1) = ( \stackrel{18/8}{14/4} )

x(2) = ( \stackrel{18/8}{71/16} )

but now I am not sure what is meant by prior error bound, compare with the actual error?

d) do i just keep doing it out till i get within .001? (aghhhhh)
 
Physics news on Phys.org
but now I am not sure what is meant by prior error bound, compare with the actual error?

It's the error estimate that can be obtained before the actual iteration's calculus. There's an expression for it in terms of the matrixes.

do i just keep doing it out till i get within .001?

No. You use the expression for the a priori error (it depends on n) to find n.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
6
Views
2K
Replies
4
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
6K
  • · Replies 10 ·
Replies
10
Views
3K