Jetski propulsion analysis (fluid dynamics)

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SUMMARY

This discussion focuses on the fluid dynamics of jetski propulsion, specifically analyzing the mass flow rate, drag force, and drag-area coefficient at various speeds. The mass flow rate of water through the jet pump is constant, with a combined mass of the rider and jetski at 450kg. At a maximum velocity of 18m/s, the thrust force equals the drag force, allowing for the calculation of drag force and drag-area coefficient using the formula CDA = 2DρV². The discussion emphasizes the use of control volumes and conservation of momentum principles to solve the problem effectively.

PREREQUISITES
  • Fluid dynamics principles, particularly mass flow rate and drag force calculations.
  • Understanding of control volume analysis in fluid mechanics.
  • Familiarity with the conservation of momentum equations.
  • Proficiency in using Excel or MATLAB for plotting and solving dynamic equations.
NEXT STEPS
  • Calculate the mass flow rate of water through the jet pump using the given parameters.
  • Determine the drag force acting on the jetski at 18m/s using conservation of momentum.
  • Compute the drag-area coefficient (CDA) for the jetski at the specified operating condition.
  • Use MATLAB to plot thrust, acceleration, velocity, and distance versus time for the jetski's acceleration from 0m/s to 16m/s.
USEFUL FOR

Students and professionals in mechanical engineering, particularly those specializing in fluid dynamics, propulsion systems, and performance analysis of watercraft.

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Homework Statement


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http://imgur.com/TQf2TNP
http://imgur.com/TQf2TNP
Diagram for the porblem
For this problem, you may assume the following:
• The mass flow rate of water through the jet pump is always the same.
• The combined mass of the rider and jetski is 450kg
• The time dependent change of fluid velocity in the jet pump apparatus is negligible.
• The drag area coefficient: CDA =
2D
ρV 2 is a constant for the whole problem.
• The jet velocity is 21m/s relative to the jetski.
1• The inlet is circular with radius 0.15m and is horizonatally oriented.
• For forward operation, the water exits the jetski in the horizontal direction only.
• The jet exits from a circular hole with radius 0.075m
Answer the following & clearly state all assumptions. Draw and label control
volumes.
1. Determine the mass flow rate of water through the jet-pump system. Clearly draw and label
your CV. You may assume the jet has a uniform velocity at the entrance and exit for this
question and subsequent questions.
2. At the top jetski velocity (Vmax = 18m/s), the thrust force equals the drag force. Determine
the drag force acting on the jetski at 18m/s? Draw and clearly label your control volume.
3. The drag-area coefficient (CDA) of the jetski can be computed as CDA =2DρV 2 . Determine
the drag-area coefficient for the 18m/s operating condition.
4. Assuming the drag-area is the same at all speeds, approximate the time it takes for the jetski
to accelerate from 0m/s to 16m/s, assuming that the exit jet velocity is always 21m/s relative
to the jetski. Plot the thrust vs. time, the acceleration vs. time, the velocity vs. time and
the distance vs. time. You will find it easier to use Excel or Matlab to solve this problem
(again: u =dxdt 'u(t+∆t)−u(t)∆t).

Homework Equations


Stated Above

The Attempt at a Solution


For the first part, i was able to figure out that Mass flow rate in is equal to flow rate out and enough variables to solve it.
The problem with the second question is how to set up the conservation of momentum equation and factor in thrust and drag in it with relative velocities.

Thank
 
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For part 2, the jet ski is traveling at constant velocity. So you can use a stationary frame of reference, or you can use a frame of reference which is moving with the jet ski. Both frames of reference are inertial, so either is acceptable. Using the jet ski as a control volume, what is the rate of change of momentum of the water passing through the jet pump?

Chet
 

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