Joint distribution of sequential variables

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Gear300
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Homework Statement
Let us choose at random a point from the interval (0,1) and let the random variable X1 be equal to the number which corresponds to that point. Then choose a point at random from the interval (0,x1), where x1 is the experimental value of X1; and let the random variable X2 be equal to the number which corresponds to this point.
(a) The marginal pdf f(x1) is intuitively uniform(0,1), and the conditional pdf f(x2|x1) is intuitively uniform(0,x1).
(b) What is the probability of X1 + X2 > 1?
(c) What is conditional mean E[X1|x2]?
Relevant Equations
Bayes' law: P(A|B) = P(A ##\cap## B)/P(B).
I am not too sure about parts (b) and (c). I guess it's reasonable to speak of a joint distribution of (X1,X2) after drawing both points.
 
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You should show us some work on a homework problem before we can give you some hints.
You can start with drawing the possible area on a square with X1, X2 axes and see if that helps you to write down the equations needed.
 
The set of possible points should be that half triangular area in the unit square where x2 < x1. But I don't think it is uniformly distributed, since otherwise the marginal distribution of X1 would not be uniform. (Haha, silly problem I know, but I had to ask since I'm not sure.)
 
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FactChecker said:
You should show us some work on a homework problem before we can give you some hints.
You could try drawing the area that satisfies X1 + X2 > 1 on a graph with x2, p(X2=x2) axes and see if that helps.
 
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Sorry for the belated reply. I guess I could try simulating it to see if I find something. Do I even need to find the joint distribution to answer parts (b) and (c)?
 
Gear300 said:
I guess I could try simulating it to see if I find something.

Simulation is a good way to verify an answer (I did just that here), but will not help you learn anything.

Gear300 said:
Do I even need to find the joint distribution to answer parts (b) and (c)?

No. For part (b) sketch the graph I suggested in #2. For part (c) think about another way of writing ## E(AB) ##.