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In both cases the algebraic multiplicty is 7, minimal and geometric multiplicities are both 3.

Why does this mean knowing these multiplicies is not enough to deduce the Jordan normal form?

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- Thread starter Ted123
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- #1

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In both cases the algebraic multiplicty is 7, minimal and geometric multiplicities are both 3.

Why does this mean knowing these multiplicies is not enough to deduce the Jordan normal form?

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