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Jordan normal form

  1. Nov 10, 2011 #1
    2z7ifpl.jpg

    In both cases the algebraic multiplicty is 7, minimal and geometric multiplicities are both 3.

    Why does this mean knowing these multiplicies is not enough to deduce the Jordan normal form?
     
  2. jcsd
  3. Nov 10, 2011 #2

    Office_Shredder

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    Because those matrices have different Jordan normal forms even though all the multiplicities are the same
     
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