K, the idealized surface current density

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SUMMARY

The discussion centers on the concept of K, the idealized surface current density, as defined in Griffiths' textbook on Electromagnetism. K is rigorously defined as the current per unit width perpendicular to the flow, expressed mathematically as K = dI/dl⊥. An integral form for surface current density is also provided: I_{surface} = ∫K·dl. The conversation highlights the relationship between surface current density and vector potential A, particularly in the context of permeable media.

PREREQUISITES
  • Understanding of surface current density in electromagnetism
  • Familiarity with Griffiths' "Introduction to Electrodynamics"
  • Basic knowledge of vector calculus
  • Concept of permeable media in physics
NEXT STEPS
  • Study the integral form of surface current density in electromagnetism
  • Explore the relationship between surface current density and vector potential A
  • Research the properties of permeable media and their implications in electromagnetic theory
  • Review relevant sections in Griffiths' textbook for deeper insights
USEFUL FOR

Students preparing for exams in Electromagnetism, particularly those studying from Griffiths' textbook, as well as educators and anyone seeking to clarify the concept of surface current density K.

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K, the "idealized surface current density"

Hey, I don't quite understand that guy, K.

I have an exam on Sunday in E&M, I'm studying from Jackson. I haven't found any definition of 'K'.

If anyone could give me a rigurous definition and an integral form, if there's any, I'd appreciate it.
Oh, and since we're at it, I stumped into that next statement:
"Suppose that the upper half of space is filled with a permeable media, while the other half is empty space. If, in the x-y plane, K is in the x direction, it follows that A (vector potential) is also in that direction in the entire space".
Huh?
 
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What definition do you have so far with which you are unsatisfied?

Griffiths (pp.211) gives the following definition: "When charge flows over a surface, we describe it by the surface current density K, defined as follows: Consider a "ribbon" of infinitesimal width dl_\perp, running parallel to the flow. If the current in this ribbon is d\vec{I}, the surface current density is

\vec{K}=\frac{d\vec{I}}{dl_\perp}

In words, K is the current per unit width-perpendicular -to-flow. In particular, if the (mobile) surface charge density is \sigma and the velocity is \vec{v}, then

\vec{K}=\sigma \vec{v}"

It is not written but I believe we can write the integral form as

I_{surface} = \int_{\mathcal{P}}\vec{K}\cdot d\vec{l}

where \mathcal{P} is a path across the surface.
 
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Thanks.
But then, in the statement I gave, why is A in the x direction? I just can't see it.
 
I don't know what permeable means, I'll have to leave that one to someone else.
 
It may not be the right term. It simply means it's a linear matter for some 'miu'.
 

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