KCL nodal analysis and power dissipation in resistor

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hdp12
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Homework Statement


Here is the homework problem I was given:​
Circuit schematic with current source Is, resistors R1, Rv, R2, R0, voltage source Vs, nodes V1, V2 and Vo, and a Load label on the far right.


The Attempt at a Solution


Handwritten KCL nodal analysis: Node 1 equation Is + (Vs - V1)/Rv + (0 - V1)/R1 = 0, Node 2 equation -Vs + (0 - V2)/R1 + (0 - V2)/(R2 + R0) = 0, V1 = 2 V, V2 = -6.4, V3 = -2.133, I0 = 0.5333, P = VI = 1.1376.


Above is the work that I began, however, I have an overwhelming feeling that I am incorrect and also I don't know how to continue to the next part/parts. Would someone please help me?
Thank you
H
 
I haven't checked each part, but I do see an issue: note that in your second equation, you've got a voltage plus a current. Any time you're adding different units, something has gone wrong.
 
Last edited:
axmls said:
I haven't checked each part, but I do see an issue: note that in your second equation, you' a got a voltage plus a current. Any time you're adding different units, something has gone wrong.
You're right, I can't do that..
Is the Voltage at the second node equal to the Voltage source, since there's nothing in between the Voltage source and the node?
 
hdp12 said:
You're right, I can't do that..
Is the Voltage at the second node equal to the Voltage source, since there's nothing in between the Voltage source and the node?
no. there is a resistor AND a voltage source in between the two nodes. If you want to do nodal anlysis you'll need to use a 'supernode'