KCL Question: Determine Currents

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Homework Statement


Determine the current in each branch of the circuit in the below diagram.
http://img341.imageshack.us/img341/7901/kclquestion.jpg

Homework Equations


V=IR
P=VI

The Attempt at a Solution


This is what i have done but it is incorrect.
Vtotal=16V
V=IR
[tex]Io1=\frac{16.00}{8.00}[/tex]
=2.00A

[tex]Io2=\frac{16}{6}[/tex]
=0.75A

[tex]Io3=\frac{16}{1}+\frac{16}{3}[/tex]
=21.3A

P.S
 
Last edited by a moderator:
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Paymemoney said:

Homework Statement


Determine the current in each branch of the circuit in the below diagram.
http://img341.imageshack.us/img341/7901/kclquestion.jpg

Homework Equations


V=IR
P=VI

The Attempt at a Solution


This is what i have done but it is incorrect.
Vtotal=16V
V=IR
[tex]Io1=\frac{16.00}{8.00}[/tex]
=2.00A

[tex]Io2=\frac{16}{6}[/tex]
=0.75A

[tex]Io3=\frac{16}{1}+\frac{16}{3}[/tex]
=21.3A

P.S

You are not writing the simultaneous KCL equations as far as I can tell. Combine series resistors where you can, and write the 1 KCL equation for this circuit (why just 1?). Then solve it.
 
Last edited by a moderator:
Use mesh analysis and KVL
 
Zayer said:
Use mesh analysis and KVL

Is there a reason to pick KVL over KCL here? Just curious.
 
After redoing the question this is what i have done:

Three equations:

Equation 1: Io3=Io1+1o2

Equation 2: 8-(4)Io2-(6)Io3=0

Equation 3: 4-(8)Io1-(6)Io2=0

Substitute Equation 1 into Equation 2
Equation 4
8-(4)Io2-(6)(Io1+Io2)=0
8=(10)Io2+(6)Io1

Equation 4 - Equation 3

8=(10)Io2+(6)Io1 - 4=(8)Io1+(6)Io2

Io2=0.90Amps

Substitute Io2 into Equation 3

Io1=\frac{4-(6*0.90)}{8}

=0.175Amps
Subsitute Io1 and Io2 into Equation 1

Io3=Io1+Io2
=0.90+0.175
=1.075Amps

I checked with the book's answers and my solutions are incorrect. Can someone tell me where i have gone wrong.
 
I do not understand your equations. Are they meant to be KCL equations? The KCL only involves the voltage at that top node, and the 3 currents that flow out of that node.
 
yes they are KCL equations
 
ok thanks i know how to do it now.