KD calculations (Organic chem lab)

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Discussion Overview

The discussion revolves around calculating the relative volume of chloroform and water needed to extract 90% of caffeine using the distribution coefficient (KD) in an organic chemistry lab context. Participants explore the relationship between concentrations and volumes in the extraction process.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant states that KD is defined as Co/Cw and expresses confusion about needing solubility information to solve the extraction problem.
  • Another participant suggests assuming that solubility limits are not exceeded in the extraction process.
  • A request for hints on how to start the problem leads to a suggestion to express the extraction condition in terms of volumes and concentrations using symbols.
  • Concerns are raised about the lack of prior discussion on relevant concepts in the lab, with a participant expressing uncertainty about how to proceed without specific values.
  • Participants discuss the importance of understanding the number of moles of caffeine in both chloroform and water solutions and what it means to have 90% extracted.
  • One participant proposes assuming real values to simplify the problem, while confirming that KD remains as Cc/Cw=10.
  • A participant claims to have solved the problem, suggesting a ratio of 10:9 for the volumes of chloroform to water.
  • Another participant humorously questions whether the ratio should be 10:9 or 9:10.

Areas of Agreement / Disagreement

Participants express varying levels of understanding and assumptions about the problem, with no consensus reached on the approach or final ratio. Some participants are confident in their calculations, while others remain uncertain about the underlying principles.

Contextual Notes

Participants highlight the absence of specific values and prior knowledge as limitations in solving the problem. The discussion also reflects a reliance on assumptions regarding solubility and extraction efficiency.

ChemDoodle
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Chloroform is used to extract caffeine from water.If the distribution coefficient, KD=10.What relative volume of chloroform-water should be used to extract 90% of the caffeine present in one single extraction?

Now i know that KD=Co/Cw and I've solved a question on how much weight of an acid will be removed by extraction.But I'm lost here..don't i need the solubility of the products to solve this?
 
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No, just assume it was not exceeded.

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Can u give me a hint on how to solve it? Like how to start?
 
Try to express the condition (90%) in terms of volumes of water and chloroform, and concentrations of caffeine in both. Name them Vc, Vw, Cc, Cw and use these symbols.

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methods
 
Okkk..so the lab instructor didnt discuss ANY of this in the lab.She just mentioned the whole KD=co/cw thing,she didnt even stress on it..So I'm clueless..really.Sorry for being a pain..but a little more help,please?
 
I suppose these thing were not discussed just like multiplication table wasn't - you are expected to already know it :wink:

How many moles of caffeine in Vc of Cc chloroform solution?

How many moles of caffeine in Vw of Cw water solution?

How many moles total?

What does it mean '90% extracted'?

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methods
 
But how am i supposed to know any of this?
n=c/v but i have none of these values.All i have is the 90% caffeine..so should i assume it to be 1L & take 90% of that?
Another thing, KD=Cc/Cw=10 in this case?
 
Don't worry about not knowing values - you are interested in ratio only, and it can be found using only symbols. However, if the symbols throw you off, try to assume some real values - say 10 mL and 0.01M.

And yes - KD=Cc/Cw=10.

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methods
 
Thankyouu..i solved it :D Its 10:9?
 
  • #10
10:9 or 9:10 :wink:

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methods
 

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