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Killing tensor notation quick questions
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[QUOTE="binbagsss, post: 4964401, member: 252335"] My notes read that, the quantity ##K^{2}=K_{uv}V^{u}V^{v}## is constant along geodesics, where ##K## is a killing vector. I know my definition that the quantity on the RHS is conserved, I'm just wondering why do we call it ##K^{2}##, rather than anything else? In analogy to a killing vector, if ##K## was a killing vector, would we instead call this ##L## or whatver, b[B]ut without a squared sign?[/B] Thanks in advance for any guidance, or a point towards some notes on this. [/QUOTE]
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Killing tensor notation quick questions
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