Kinamatics problem oh physics elders

In summary: Then, use the equation for velocity in terms of t to find the max height and flight time. Once you have these values, you can plug them into the distance equation to find the horizontal distance traveled.In summary, to solve this kinematics problem, you will need to use the equations for vertical and horizontal distances, as well as the given equations for velocity and time. By setting the y equation for velocity equal to 0, you can find the time at maximum height. Then, take the derivative of the distance equation with respect to time to find the velocity in terms of time. This can be used to find the max height and flight time. Finally, plug these values into the distance equation to find the horizontal distance traveled.
  • #1
Zizfizziks
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Kinamatics problem please help oh physics elders :)

1. A person shoots off a shotgun so that we know the muzzle velocity is 2,200 ft / sec. If that shooter is standing in such a way that the gun is angled at 15*degrees above a horizontal line 5 feet off the ground. It is given that the vertical distance can be calculated by the equation y = -G/2 t 2 + Vo Sin (~)t + yo and the horizontal distance is x=Vo Cos (~) t



Relevant equations :

y = -G/2 t + Vo Sin (~)t + Yo
x=Vo Cos (~)t

Where the (~) is a theta and the o after the V and Y mean initial.



Questions.
What is the equation vertical and horizontal distances for the shooter?

(A) What time does the projectile reach max height?
(B) What is the max height?
(C) What is the flight time?
(D) How far does the projectile fly?
(E) Find an equation that models the flight path (hint: y in terms of x)
(F) What is the velocity when it hits the ground?
(G) If the 12 ft wall is put 50 ft away does the projectile hit the wall?
(H) If it does what is the velocity when it hits the wall?





Thanks so much, if anything I'm not even asking for answers but how I get them.

I have been struggling with physics homework and this is one of the ones that give me so much trouble...

 
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  • #2


When the projectile is at its maximum height, it is not moving in the y component. So, if we set the y equation for velocity equal to 0, we can find the time that it is not moving, which is also the time it is at it's maximum height.

Since you are given the distance equation in terms of t, you can find the velocity in terms of t (take the derivative).
 

Related to Kinamatics problem oh physics elders

What is kinematics?

Kinematics is the branch of physics that deals with the study of motion and its causes, without considering the forces that cause the motion.

What are the three main types of kinematics?

The three main types of kinematics are translational motion, rotational motion, and vibrational motion.

How do you solve a kinematics problem?

To solve a kinematics problem, you need to identify the known and unknown variables, choose the appropriate kinematic equations, and use algebra to solve for the unknown variable. It is important to draw a clear diagram and use the correct units for the variables.

What is the difference between kinematics and dynamics?

Kinematics deals with the study of motion without considering the forces that cause the motion, while dynamics deals with the study of motion and the forces that cause it.

What real-life applications use kinematics?

Kinematics is used in many real-life applications, such as designing roller coasters, analyzing sports movements, and predicting the motion of objects in space.

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