# Kinematic and Projectile motion equations

## Homework Statement

Find the angle of the projection for which the maximum height is equal half of the range.

## Homework Equations

Kinematic and Projectile motion equations

Just use SUVAT equations.

I'm working on the same problem. Any help would be appreciated. I've gotten as far as finding R(range)= (Vo^2sin2Theta)/g but how do I find the formula for Max height?

I'm working on the same problem. Any help would be appreciated. I've gotten as far as finding R(range)= (Vo^2sin2Theta)/g but how do I find the formula for Max height?

$R(range)= \frac{Vo^2 Sin2\Theta}{g}$

For maximum height
(v0Sinθ)2=2aR

How did you get that equation for max height?

How did you get that equation for max height?

(vy)2=(uy)2-2as

Thank you so much :)!