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Kinematic and Projectile motion equations

  • Thread starter McDonell
  • Start date
  • #1
11
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Homework Statement



Find the angle of the projection for which the maximum height is equal half of the range.


Homework Equations



Kinematic and Projectile motion equations
 

Answers and Replies

  • #2
1,065
10
Just use SUVAT equations.
 
  • #3
27
0
I'm working on the same problem. Any help would be appreciated. I've gotten as far as finding R(range)= (Vo^2sin2Theta)/g but how do I find the formula for Max height?
 
  • #4
1,065
10
I'm working on the same problem. Any help would be appreciated. I've gotten as far as finding R(range)= (Vo^2sin2Theta)/g but how do I find the formula for Max height?
[itex]R(range)= \frac{Vo^2 Sin2\Theta}{g}[/itex]

For maximum height
(v0Sinθ)2=2aR
 
  • #5
27
0
How did you get that equation for max height?
 
  • #6
1,065
10
How did you get that equation for max height?
(vy)2=(uy)2-2as
 
  • #7
27
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Thank you so much :)!
 

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