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Kinematic and Projectile motion equations

  1. Sep 24, 2012 #1
    1. The problem statement, all variables and given/known data

    Find the angle of the projection for which the maximum height is equal half of the range.


    2. Relevant equations

    Kinematic and Projectile motion equations
     
  2. jcsd
  3. Sep 24, 2012 #2
    Just use SUVAT equations.
     
  4. Sep 24, 2012 #3
    I'm working on the same problem. Any help would be appreciated. I've gotten as far as finding R(range)= (Vo^2sin2Theta)/g but how do I find the formula for Max height?
     
  5. Sep 24, 2012 #4
    [itex]R(range)= \frac{Vo^2 Sin2\Theta}{g}[/itex]

    For maximum height
    (v0Sinθ)2=2aR
     
  6. Sep 24, 2012 #5
    How did you get that equation for max height?
     
  7. Sep 24, 2012 #6
    (vy)2=(uy)2-2as
     
  8. Sep 25, 2012 #7
    Thank you so much :)!
     
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