Kinematic Equations Used to Find A.) Average Speed & B.)Acceleration

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SUMMARY

The discussion centers on solving kinematic equations to determine a truck's original speed and acceleration. The truck covers 40.0 meters in 7.15 seconds while decelerating to a final velocity of 3.50 m/s. The correct original speed (Vo) is calculated as 12.5 m/s using the equation Δx = Vav(Δt). The acceleration (a) is found to be -1.26 m/s², but the initial calculation for Vo was incorrect due to algebraic errors.

PREREQUISITES
  • Understanding of kinematic equations, specifically Δx = Vav(Δt) and a = (V - Vo)/(Δt)
  • Basic algebra skills for solving equations
  • Familiarity with concepts of average velocity and acceleration
  • Knowledge of uniform motion and deceleration
NEXT STEPS
  • Review the derivation and application of kinematic equations in physics
  • Practice solving problems involving uniform acceleration and deceleration
  • Explore the concept of average velocity in greater detail
  • Learn about error-checking techniques in algebraic calculations
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as educators looking for examples of problem-solving in motion analysis.

lethalfresa
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Homework Statement



A truck covers 40.0m in 7.15 s while uniformly slowing down to a final velocity of 3.50 m/s. a.) Find the truck's original speed b.) Find it's acceleration



Homework Equations



Δx = Vav(Δt) = (V+Vo/2)Δt

a=(V-Vo)/(Δt)



The Attempt at a Solution



Part A.)


1.) I used the formula Δx = Vav(Δt) = (V+Vo/2)Δt

2.) Plugged in what is given & solved for Vo

40.0m=((3.50m/s=Vo)/(2))(7.15s)

Vo=12.5 m/s

Part B.)

1.) I used the formula a=(V-Vo)/(Δt)

2.)Plugged in what I have

(3.50 m/s-12.5 m/s)/(7.15s) = -1.26 m/s2

Apparently both my answers are wrong and I am not sure what I am doing wrong. I tried this multiple times, as well as other different versions of this problem which I get correctly.

Your input would be appreciated. Thanks :)
 
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lethalfresa said:
40.0m=((3.50m/s+Vo)/(2))(7.15s)

Vo=12.5 m/s
Check your algebra here.

Part B.)

1.) I used the formula a=(V-Vo)/(Δt)

2.)Plugged in what I have

(3.50 m/s-12.5 m/s)/(7.15s) = -1.26 m/s2
It will be correct when you fix your Vo. :smile:
 

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