Kinematic Question: Helicopter Height & Mailbag Release Solution | Homework Help

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SUMMARY

The problem involves calculating the time it takes for a mailbag to reach the ground after being released from a helicopter at a height defined by the equation h = 2.60t³. At t = 2.00 seconds, the helicopter's height is 20.8 meters, and the initial velocity of the mailbag is 31.2 m/s. To determine the time until the mailbag hits the ground, the quadratic equation must be applied, considering the effects of gravity on the mailbag's descent.

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grewas8
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Homework Statement



The height of a helicopter above the ground is given by h = 2.60t3 , where h is in meters and t is in seconds. After 2.00 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground?

Homework Equations



yf=y(initial) + v*delta t

The Attempt at a Solution



h = 2.60 (8) = 20.8 (height at the bag is released)
y(initial)=0
v= 7.8t^2= 31.2 m/s
i dun understand if gravity would be used here and if it is can u just use the quadratic eqn
 
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Everything you did looks good. Yes, you'll have to use the quadratic equation.
 
grewas8 said:
yf=y(initial) + v*delta t

this equation isn't right since velocity isn't constant... but you didn't use this equation.
 

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