(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The height of a helicopter above the ground is given by h = 2.55t^3, where h is in meters and t is in seconds. At t = 1.65 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground?

2. Relevant equations

The above equation, and d = 1/2at (because initial velocity is zero)

3. The attempt at a solution

2.55t^3

2.55(1.65)^3 = 11.45491875 m/s

11.45491875 = 1/2 (-9.8) (t^2)

22.9098375 = (-9.8) (t^2)

-2.3377 = t^2

You then get an imaginary number, but regardless, because time cannot be negative, I pretended like the answer was positive and took the square root.

I got uhhh 1.528966488, but when I plug it into the online homework, it's incorrect?

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# Homework Help: Time it takes for an object to hit the ground

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