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here it is. If a ball is dropped from hieght H above ground and at the same instance, a ball is released from ground vertically. Determine the speeed of the second ball if the two balls are to meet at hieght of H/2 above ground.

with that info i am stuck I know that Intial velocity of the ball dropped =0 and that to calculate it disatance h/2 will use .5at^2.

but how to equate that to the second ball I am stuck.

help would be apprieciated