Kinematics bowling ball problem

[physicsss]

a bowling ball traveling with constant speed hits the pins at the end of a bowling lane 10 m long. The bowler hears the sound of the ball hitting the pins 3 sec after the ball is released from his hands. What is the speed of the ball? (Speed of sound is 340 m/s)

Can someone give me a hint? I know it involves d=v*t, but I don't know how I can use the speed of sound and the time when the ball hits the pins besides finding the distance the ball traveled...

thanks in advance

 

[jamesrc]

The total time between releasing the ball and hearing the sound of the ball hitting the pin is given as 3 seconds. This time, T, is the sum of t₁, the time it takes the bowling ball to go down the lane, and t₂, the time it takes for the sound to travel 10m. (T = t₁ + t₂) for t₂, v = a = d/t₂, where a is the speed of sound and d is 10 m. The same equation goes for t₁: v_ball = d/t₁. (the speed of the ball is unknown) To put it all together, solve for t₁ and t₂ and plug back into the first equation I wrote. I hope that helps.

 

[physicsss]

tell me if I'm on the right track...

3=t1+t2
3=t1+(d/v)
3=t1+10/340
t1=2.97

d=vt
10=v*2.97
v=3.4 <-velocity of the ball

 

[jamesrc]

Looks good except for the second line, which looks like a typo. Speaking of which, I had a typo in my original post (fixed now, sorry about that). Anyway, good job.

 

[physicsss]

Fixed, and thank you so much for the help.