Kinematics(displacement and Velocity)

  • Thread starter Thread starter BlueOwl
  • Start date Start date
  • Tags Tags
    Velocity
Click For Summary
SUMMARY

The discussion centers on a kinematics problem involving a car that returns to its starting point after 160 seconds while traveling at an average speed of 10 m/s. The key conclusions are that the displacement of the car is zero because it starts and ends at the same location. Consequently, the average velocity, calculated as displacement divided by time, is also zero. This is confirmed through the understanding of motion graphs, specifically the position-time graph, which illustrates that there is no net change in position.

PREREQUISITES
  • Understanding of basic kinematics concepts, including displacement and velocity.
  • Familiarity with average speed calculations.
  • Knowledge of motion graphs, particularly position-time graphs.
  • Ability to interpret and analyze physical motion scenarios.
NEXT STEPS
  • Study the principles of displacement versus distance in kinematics.
  • Learn how to construct and interpret position-time graphs for various motion scenarios.
  • Explore the concept of average velocity and its calculation in different contexts.
  • Investigate real-world applications of kinematics in automotive motion analysis.
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding motion analysis and graph interpretation.

BlueOwl
Messages
8
Reaction score
0

Homework Statement



A car starts from a point and returns to the same point after 160 seconds. During this time the car traveled at an average speed of 10 m/s. What is its displacement? What is its average velocity? Explain your answers using a motion graph (Position - time)


Homework Equations





The Attempt at a Solution



Ok so I am a little confused with this one since the car starts from the same point it returns to therefore i was assuming that the displacement would be zero and considering that average velocity is displacement over change of time zero divided by 160 again the average velocity would be zero no? please help I am really confused by the same points meaning the car is going from point A to Point A again not Point A to Point B therefore i am tottally lost maybe a hint to get me started thanks .
 
Physics news on Phys.org
Hi BlueOwl,

BlueOwl said:

Homework Statement



A car starts from a point and returns to the same point after 160 seconds. During this time the car traveled at an average speed of 10 m/s. What is its displacement? What is its average velocity? Explain your answers using a motion graph (Position - time)


Homework Equations





The Attempt at a Solution



Ok so I am a little confused with this one since the car starts from the same point it returns to therefore i was assuming that the displacement would be zero and considering that average velocity is displacement over change of time zero divided by 160 again the average velocity would be zero no?

Those answers sound right to me.
 

Similar threads

“Chasing Vertices: A Time-Bound Pursuit Problem in a Square”
  • · Replies 3 ·
Replies
3
Views
1K
Why would this be accelerating positively?
  • · Replies 6 ·
Replies
6
Views
1K
Zero velocity for a time interval, what about acceleration?
  • · Replies 7 ·
Replies
7
Views
2K
Motion of an Object: Displacement & Average Velocity
  • · Replies 8 ·
Replies
8
Views
2K
Momentum: instantaneous or average?
  • · Replies 9 ·
Replies
9
Views
1K
Can terminal velocity be determined from the information given?
  • · Replies 7 ·
Replies
7
Views
1K
What is the displacement and average velocity of a classic car in a road rally?
  • · Replies 1 ·
Replies
1
Views
2K
Needs clarity on this displacement vector diagram
  • · Replies 3 ·
Replies
3
Views
1K
Why Does a Free-Falling Object Not Have Zero Final Velocity Upon Impact?
  • · Replies 22 ·
Replies
22
Views
3K
Calculate the Acceleration of this Car
  • · Replies 7 ·
Replies
7
Views
1K