Kinematics Free fall problems part 2 help

[P944]

Homework Statement

While riding on an elevator descending with a constant speed of 3.3 m/s, you accidentally drop a book from under your arm.

(a) How long does it take for the book to reach the elevator floor, 1.0 m below your arm?

(b) What is the book's speed relative to you when it hits the elevator floor?

Homework Equations

v = v0 + a*t
x = x0 + v0 *t + 1/2*a*t^2
x= x0 + v*t-1/2*a*t^2
V^2 = v0^2 +2*a*(x-x0)

The Attempt at a Solution

I tried to solve for time by first solving for final velocity using V^2 = v0^2+2*a*(x-x0) =
V^2 = (3.3m/s)^2 +2(-9.80m/s^2)(0-1m)
V^2 = 30.49 m^2/S^2
square root of 30.49 = 5.522 m/s

v = v0 +a*t
5.522 = 3.3 + (9.80)*t
t = 0.2267

part b) substract the book's velocity 5.522 - my velocity 3.3 = 2.222

I got both answers wrong. I was wondering if someone could help me explain what i did wrong? thank you so much!

 

[Char. Limit]

Shouldn't your initial velocity be negative, considering that you're descending?

 

[Logistix]

Since you're dropping the book with an initial velocity, and the rest of the falling path is accelerating, the velocity at any moment can be calculated, as you know, with:
v = v0 + at
This, however, is the velocity. If we want the distance, we have to multiply by t (vt=s)
v = v0 + at /*t
s = v0t + at^2/2
Now you can substitute s with the height of 1:
1 = 3.33t + 9.81t^2/2
Go on from here. If you have trouble extracting t which you need, it can be substituted:
v = 3.33 + 9.81t
v - 9.81t = 3.33
t = v-3.33/9.81
Insert it into the previous expression:
1 = 3.33(v-3.33/9.81) + 9.81*(v-3.33/9.81)^2/2
Hope you can work it out from here (you'll get the final v and from that the t).
Good luck!