- #1
lmbiango
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Kinematics! I think it's right, but the computer says NO
An airplane is flying with a velocity of 240 m/s at an angle of 30.0° with the horizontal, as the drawing shows. When the altitude of the plane is 2.4 km, a flare is released from the plane. The flare hits the target on the ground. What is the angle theta?
(the angle is between the ground and the line of sight from the plane to the target. So it is the angle between the adjacent side (the ground) and the hypotenuse of a right triangle with the opposite side being 2.4km)
There was a diagram with this, but it's pretty self explanatory.
Vxo = 240(cos(30)) = 207.8 m/s
Vyo = 240(sin(30)) = 120 m/s
Vf^2 - Vi^2 = 2a (change in X)
Vy^2 - 120^2 = 2(9.8)(2400)
Vy^2 = 247.87 m/s
(wrong!)
and theta:
the inverse tangent of (247.87/207.8)
=50.01 degrees
Also wrong.
I have no idea where I could have gone wrong. I thought I had this one!
Please help - I used 4 out of 5 of my attempts and it's due tomorrow!
An airplane is flying with a velocity of 240 m/s at an angle of 30.0° with the horizontal, as the drawing shows. When the altitude of the plane is 2.4 km, a flare is released from the plane. The flare hits the target on the ground. What is the angle theta?
(the angle is between the ground and the line of sight from the plane to the target. So it is the angle between the adjacent side (the ground) and the hypotenuse of a right triangle with the opposite side being 2.4km)
There was a diagram with this, but it's pretty self explanatory.
Vxo = 240(cos(30)) = 207.8 m/s
Vyo = 240(sin(30)) = 120 m/s
Vf^2 - Vi^2 = 2a (change in X)
Vy^2 - 120^2 = 2(9.8)(2400)
Vy^2 = 247.87 m/s
(wrong!)
and theta:
the inverse tangent of (247.87/207.8)
=50.01 degrees
Also wrong.
I have no idea where I could have gone wrong. I thought I had this one!
Please help - I used 4 out of 5 of my attempts and it's due tomorrow!