High School Understanding Kinematics in Calculus for High School Students

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High school students learning calculus can apply integration and differentiation methods to kinematics, particularly in understanding displacement, velocity, and acceleration. The phrase "in the second second" refers to the time interval from t=1s to t=2s, indicating how to calculate displacement during that specific second using integration. It is clarified that "meters per second" denotes velocity, while "meters per second per second" indicates acceleration. Integrating acceleration over time yields velocity, and integrating velocity over time yields distance. The discussion emphasizes the importance of clear terminology in understanding these concepts.
solarmidnightrose
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hi, I'm a high-school student that is just beginning to learn calculus.
in calculus we are learning how to apply integration and diffrentiaiton methods regarding kinematics.

there is this certain phrase i do not really understand in our textbook: e.g."in the second second"
how am i meant to write "in the second second" when I'm integrating? It would be nice if you included an example.

thanks :)
Oh, and Please remember I am a high-school student that doesn't understand complex terminology yet.
 
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Did you mean “meters per second” and “meters per second per second” but in another language translated to English?

In the first case of meters per second that is speed or velocity

In the second case of meters per second per second that is acceleration.

Integrating acceleration over time gets you the velocity and integrating velocity over time gets you distance.
 
solarmidnightrose said:
there is this certain phrase i do not really understand in our textbook: e.g."in the second second"
how am i meant to write "in the second second" when I'm integrating? It would be nice if you included an example.

Could it mean this?

"in the first second" means t=0{\rm\ s} to t=1{\rm\ s}. So, the displacement during the first second is \int_0^1 v dt
"in the second second" means t=1{\rm\ s} to t=2{\rm\ s}. The displacement during the second second is \int_1^2 v dt
"in the third second" means t=2{\rm\ s} to t=3{\rm\ s}, etc.
 
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solarmidnightrose said:
in the second second"

robphy said:
Could it mean this?

"in the first second" means t=0 to t=1 <snip>
I'm pretty sure that's what was intended. Writing "second second" is a little confusing, in that the first word is an ordinal (e.g., first, second,, third, etc.) while the next word is a time interval.
 
robphy said:
Could it mean this?

"in the first second" means t=0{\rm\ s} to t=1{\rm\ s}. So, the displacement during the first second is \int_0^1 v dt
"in the second second" means t=1{\rm\ s} to t=2{\rm\ s}. The displacement during the second second is \int_1^2 v dt
"in the third second" means t=2{\rm\ s} to t=3{\rm\ s}, etc.
Thank You Soooooo Much 'robphy'! This makes soo much sense now :)
 
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jedishrfu said:
Did you mean “meters per second” and “meters per second per second” but in another language translated to English?

In the first case of meters per second that is speed or velocity

In the second case of meters per second per second that is acceleration.

Integrating acceleration over time gets you the velocity and integrating velocity over time gets you distance.

Thanks 'jedishrfu' :) Sorry if my description didn't make sense, but what you've said has also proved a useful reminder for myself.
 
Mark44 said:
I'm pretty sure that's what was intended. Writing "second second" is a little confusing, in that the first word is an ordinal (e.g., first, second,, third, etc.) while the next word is a time interval.

Yeah, you're right 'Mark44'. That was exactly what I meant.
I guess I did choose a confusing example to explain my confusion.
 

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