How Do You Calculate Height Without Acceleration in Physics Problems?

  • Thread starter Thread starter Har2803
  • Start date Start date
  • Tags Tags
    parts Physics
Click For Summary
SUMMARY

The discussion focuses on calculating height in physics problems without direct acceleration data. Participants emphasize the importance of gravitational acceleration, denoted as g, which is typically 9.81 m/s² on Earth. The conversation highlights the confusion surrounding the initial vertical velocity, with one user mentioning values of 350 m/s and 250 m/s for initial and horizontal velocities, respectively. The consensus is that without sufficient data, particularly the correct application of kinematic equations, determining height becomes problematic.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of gravitational acceleration (g = 9.81 m/s²)
  • Familiarity with initial velocity concepts (both vertical and horizontal)
  • Ability to interpret problem data in physics contexts
NEXT STEPS
  • Review kinematic equations for vertical motion in physics
  • Study the concept of gravitational acceleration and its implications
  • Learn how to resolve initial velocity into vertical and horizontal components
  • Practice solving physics problems involving height calculations without direct acceleration data
USEFUL FOR

Students studying physics, educators teaching motion concepts, and anyone seeking to improve their problem-solving skills in kinematics.

Har2803
Messages
2
Reaction score
2
Homework Statement
A bomb of mass 15.0 kg with an initial velocity of 350 m/s and horizontal velocity of 250 m/s is
projected from the edge of a cliff of a height 500 m. The kinetic energy just before it hits the target
is 500 kJ.
(a) Determine the initial kinetic energy of the bomb.
[2 Marks]
(b) Show the change of kinetic energy of the bomb.
[2 Mark]
(c) Find the value of the initial angle.
[2 Marks]
(d) Calculate the height of the target from the ground.
[4 Marks]
(e) Determine the kinetic energy and velocity at the height of 2.50 × 103 m from the
ground? [5 Marks]
Relevant Equations
v^2=u^2+2as
For parts (d) and (e) I can't figure out the required steps to get the height due to the fact that I don't have the acceleration. I may have done a miscalculation for the former questions as well. I also feel (e) requires the value of a. Hope someone can help me out. Been going at this question for 2 days now.
 
  • Like
Likes   Reactions: Delta2
Physics news on Phys.org
Isn't the movement of the bomb inside the gravitational field of earth?
Isn't the gravitational acceleration of earth, g, given by the problem?

If g is not given by the problem data, then we should be able to find it from other given data, but i am afraid the given data is not enough to find g.
 
Last edited:
  • Like
Likes   Reactions: Har2803
Delta2 said:
Isn't the movement of the bomb inside the gravitational field of earth?
Isn't the gravitational acceleration of earth, g, given by the problem?

If g is not given by the problem data, then we should be able to find it from other given data, but i am afraid the given data is not enough to find g.
That is what I thought as well initially. If i use 9.81 as the value of a in a kinematic eq, I still can't find the height of the target from the ground. I just end up with a value that proves the target is not lifted off the ground at all
 
  • Like
Likes   Reactions: Delta2
Hmmm you got to show us your workings, but let me ask this do you get a negative value for the height of the target?
 
Har2803 said:
initial velocity of 350 m/s and horizontal velocity of 250 m/s
Something missing? Should that be initial vertical velocity of 350 m/s (up or down?) or perhaps initial speed?
 

Similar threads

  • · Replies 42 ·
2
Replies
42
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 40 ·
2
Replies
40
Views
3K
  • · Replies 15 ·
Replies
15
Views
3K
Replies
18
Views
3K
  • · Replies 64 ·
3
Replies
64
Views
6K
  • · Replies 11 ·
Replies
11
Views
2K