How far does the police car travel to catch a speeder traveling at 180 km/hr?

  • Thread starter Thread starter Neal Parikh
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    Car Kinematics
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SUMMARY

The problem involves a police car at rest pursuing a speeder traveling at a constant speed of 180 km/hr (50 m/s) while accelerating at 3.7 m/s². To determine the distance the police car travels to catch the speeder, the relevant kinematic equations include x = x₀ + v₀t + 1/2at² and V² = v₀² + 2a(x - x₀). The initial position (x₀) of the police car is 0, and its initial velocity (v₀) is also 0. The conversion of the speeder's speed to meters per second is essential for consistent unit application.

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Homework Statement


A police car at rest, is passed by a speeder traveling at constant speed of 180 km/hr, take off in hot pursuit accelerating at 3.7 m/s². How far has the police car traveled to catch the speeder?

Homework Equations


I think we would use x = xo + volt + 1/2at^2[/B]

(Or maybe V^2 = vo^2 + 2a(x-xo)?I am getting confused with which equations are relevant).

The Attempt at a Solution


I know xo is 0 because it is the start position at rest, volt is also 0 because its not moving. I am confused as to what I do with the 180 km/hr (I converted to 50 m/s)
 
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Definitely want to convert to m/s so that all the units are the same. I would also write out what you know about each car. Treat them as separate questions.
 

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