Kinematics Physics equation, simple explanation.

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SUMMARY

The discussion focuses on calculating the minimum acceleration required to safely pass a slow driver using kinematics equations. The scenario involves a passing lane of 1 km, with a slow car traveling at 70 km/h and an oncoming truck at 80 km/h. Participants analyze the equation d = vt, attempting to manipulate it to account for the distances and speeds of both vehicles. The correct formulation should consider the total distance of 1044 meters for accurate time calculations during the passing maneuver.

PREREQUISITES
  • Understanding of basic kinematics equations, specifically d = vt.
  • Knowledge of relative velocity concepts in physics.
  • Familiarity with unit conversions, particularly between kilometers per hour and meters per second.
  • Ability to manipulate algebraic equations to solve for unknown variables.
NEXT STEPS
  • Study the derivation of kinematic equations in physics.
  • Learn about relative motion and how it applies to passing scenarios.
  • Explore practical applications of kinematics in real-world driving situations.
  • Practice solving problems involving acceleration, distance, and time using various examples.
USEFUL FOR

This discussion is beneficial for physics students, driving instructors, and anyone interested in understanding the principles of motion and safe driving practices during overtaking maneuvers.

LeopardGecko
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You are stuck behind a slow driver, there is a 1 km passing lane between a slow car and a truck. In order to properly pass you must be at least 40m from the slow car. You are traveling at 70km/h and there is an oncoming truck traveling at 80km/h. Each car is 4m long. What is the minimum acceleration you would need.

Figuring out the final answer isn't the problem, just the manipulation of the next equation to find maximum time it would take. I don't get how this works out, could somebody should me step by step on how to turn d = vt into:

d = v(car)t + d + v(truck)t

Basically what two equations does he combine together to make this equation up above?

Entering numerical values makes it:

1000m = v(you)t + 44 + v(truck)t
 
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LeopardGecko said:
d = v(car)t + d + v(truck)t
Are you sure you wrote the same equation as you saw it? This equation simplifies to

v(car) = v(truck)​

which is wrong.
 
Yeah, it is exactly as I saw it. Minus where I added in car and truck in parenthesis, but that was implied by the question.

The next step in the equation is

956 = t(70+80)

Which makes doesn't make sense as this is now the total distance you have to pass when you're beside the other car and doesn't account for the time that you and the truck had moved by the time "your" car had moved up to the "slow car".

It would make sense if when the variables where entered it would be 1044m = t(70+80).
 

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