Kinematics[polar coordinate] concept problem

1. Nov 19, 2007

sunumen

2. Nov 20, 2007

rl.bhat

The car has two velocity components. The horizontal component Vr = r*omega. It is given that h = cos(2theta) + 1. Therefore vertical component of the velocity Vh = dh/dt = -2sin(2theta)*d(theta)/dt.
The resultant of Vr and Vh gives the velocity of the car.

3. Nov 20, 2007

azatkgz

$$v(\theta)=\omega R(\theta)$$

Distance of car to vertical shift is always changing and equals $$R(\theta)$$

4. Nov 20, 2007

rl.bhat

This variation is along the radius and hence it does not affect the theta component of the velocity.

5. Nov 20, 2007

azatkgz

But theta is on x-y plane

$$\omega=\frac{d\theta}{dt}$$

Last edited: Nov 20, 2007
6. Nov 21, 2007

rl.bhat

Distance of car to vertical shift is always changing and equals Rcos(phy) This velocity does not contribute to V(theta)