1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Kinematics[polar coordinate] concept problem

  1. Nov 19, 2007 #1
  2. jcsd
  3. Nov 20, 2007 #2

    rl.bhat

    User Avatar
    Homework Helper

    The car has two velocity components. The horizontal component Vr = r*omega. It is given that h = cos(2theta) + 1. Therefore vertical component of the velocity Vh = dh/dt = -2sin(2theta)*d(theta)/dt.
    The resultant of Vr and Vh gives the velocity of the car.
     
  4. Nov 20, 2007 #3
    [tex]v(\theta)=\omega R(\theta)[/tex]

    Distance of car to vertical shift is always changing and equals [tex]R(\theta)[/tex]
     
  5. Nov 20, 2007 #4

    rl.bhat

    User Avatar
    Homework Helper

    This variation is along the radius and hence it does not affect the theta component of the velocity.
     
  6. Nov 20, 2007 #5
    But theta is on x-y plane

    [tex]\omega=\frac{d\theta}{dt}[/tex]
     
    Last edited: Nov 20, 2007
  7. Nov 21, 2007 #6

    rl.bhat

    User Avatar
    Homework Helper

    Distance of car to vertical shift is always changing and equals Rcos(phy) This velocity does not contribute to V(theta)
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Kinematics[polar coordinate] concept problem
Loading...