# Kinematics[polar coordinate] concept problem

1. Nov 19, 2007

### sunumen

2. Nov 20, 2007

### rl.bhat

The car has two velocity components. The horizontal component Vr = r*omega. It is given that h = cos(2theta) + 1. Therefore vertical component of the velocity Vh = dh/dt = -2sin(2theta)*d(theta)/dt.
The resultant of Vr and Vh gives the velocity of the car.

3. Nov 20, 2007

### azatkgz

$$v(\theta)=\omega R(\theta)$$

Distance of car to vertical shift is always changing and equals $$R(\theta)$$

4. Nov 20, 2007

### rl.bhat

This variation is along the radius and hence it does not affect the theta component of the velocity.

5. Nov 20, 2007

### azatkgz

But theta is on x-y plane

$$\omega=\frac{d\theta}{dt}$$

Last edited: Nov 20, 2007
6. Nov 21, 2007

### rl.bhat

Distance of car to vertical shift is always changing and equals Rcos(phy) This velocity does not contribute to V(theta)