Kinematics Problem -- 3 particles at the vertices of an equilateral triangle

[RandomGuy1]

Here's the question:

Three particles A, B and C are situated at the vertices of an equilateral triangle ABC of side d at time t = 0. Each of the particles moves with constant speed v. The particle at A always has its velocity along AB, B along BC and C along CA. At what time will the particles meet?

And here's what I don't understand - If each particle is restricted to its corresponding side of the triangle, how exactly will they "meet"?

 

[Chestermiller]

The sides of the triangle are getting smaller.

 

[Doc Al]

The particle at A always has its velocity along AB, B along BC and C along CA.

It's a bit oddly worded. Don't think in terms of fixed directions based on the original positions. As the particles move and change position: A always moves toward B, B always moves toward C, C always moves toward A.

 

[RandomGuy1]

It's a bit oddly worded. Don't think in terms of fixed directions based on the original positions. As the particles move and change position: A always moves toward B, B always moves toward C, C always moves toward A.

You were right. That cleared a lot up. Thanks!