How to Solve the Kinematics Ratio Problem for a Particle's Journey?

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To solve the kinematics ratio problem for a particle's journey, the key is understanding the time taken to reach different heights during projectile motion. The particle takes time 't1' to reach 15/16 of the maximum height 'H' and time 't2' to descend from that height to the ground. The equations of motion can be applied, but it's crucial to recognize that t2 will be greater than t1 due to the nature of free fall. The discussion suggests that common ratios like 1:3, 3:1, 5:3, and 3:5 can be evaluated based on the relationship between the distances and times involved. Ultimately, a deeper understanding of the motion equations and the specific distances covered can lead to the correct ratio.
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I was given this worksheet from my teacher and well I am finding it really tough so far .. the question below is just crushing my skull .. so i would appreciate it if you guys would guide me through it

"A particle projected from ground takes time 't1' to reach 15/16 H and time 't2' to cover the rest of distance to the ground. If 'H' is the maximum height attained. find the ratio t1: t2

well my options were many ... they were 1:3 ,3:1, 5:3 and 3:5

and well using my knowledge of atleast what i know is: 1)the object has almost reached the max height so the ratio won't be that big 2)i tried using the equations of motions and to no avail i still didnt get anywhere 3)[usin(thetha)(t1)]-[(1/2)g(t1)^2]=(15/16)H 4)and [(usin(thetha)^2]/2g=H

keeping in mind that t2 has to obviously be greater than t1 ... the second and the third options are eliminated ... well it surely can't be 1:3(maybe) .. because that is a really big ratio ...

is there some other extra formula or something other than the common formulae (like max height and range and splitting of vectors)i am supposed to know to solve this question am i missing out anything?
 
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Try this. How long does it take to fall from a height H? How long does it take to fall a distance H/16?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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