Kinetic and Potential Energy rollercoaster

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Homework Help Overview

The discussion revolves around a physics problem involving kinetic and potential energy in the context of a roller coaster ride. The scenario includes a roller coaster modeled as a particle moving between two points, A and B, with given speeds and a specific incline.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between potential energy, kinetic energy, and work done against resistance forces. Questions arise regarding the calculations of energy at points A and B, and the inclusion of kinetic energy at point A.

Discussion Status

Some participants have offered guidance on checking energy calculations and considering all forms of energy involved. There is an acknowledgment of potential miscalculations, particularly regarding the use of radians in calculations. Multiple interpretations of the problem are being explored.

Contextual Notes

Participants note the importance of ensuring all relevant information is provided and the potential for misunderstanding due to calculation methods, such as the use of radians versus degrees.

Gregg
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Homework Statement



The diagram shows part of the track of aroller coaster ride, which has been modeled as numbner of straight lengths of track. The roller coaster's carriages are modeled as a particle of mass 400kg which can negotiate bends A, B, C and D without any loss of speed. The speed of the roller coaster as A is 3m/s and at B it is 10m/s.

(a) Show that the work done against the resistance forces as the roller coaster moves from A to B is approx 8610J and use this to find the magnitude of the resistance forces assuming that they are constant.

The diagram shows a roller coaster. The relevant piece of the picture is that A is at the top of a slope and B is it the bottom. The length of the hypotenuse of these triangle (i.e. the distance from A to B) is 20m, and the incline is 20 degrees.


The Attempt at a Solution



Loss in PE = Gain in KE + Loss due to resistance

mgh = 1/2 mv^2 + R
400x9.81x20sin(20) - 18200 = R

This is not 8610J ?
 
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What you've done seems to be correct, unless there is additional information you haven't supplied us.
 
What is the total energy (potential and kinetic) of the roller coaster at A? What is the potential and Kinetic energy of the roller coaster at B? The difference in the two should be the energy lost to friction.

I think you are forgetting to include the roller coaster's kinetic energy at A, and you have only considered its potential energy.
 
Nah, he noted it down poorly but calculated \Delta mgh and \Delta 1/2 m v^2.
 
Cyosis said:
Nah, he noted it down poorly but calculated \Delta mgh and \Delta 1/2 m v^2.

Oh god. My calculator was in radians. Sorry everyone.
 

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