(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 7kg bowling ball falls from a 2m shelf. Just before hitting the floor, what will its kinetic energy be? (air resistance is negligible)

2. Relevant equations

PEi + KEi = PEf + KEf

KE = 1/2mv^2

3. The attempt at a solution

m = 7kg

Δy = 2m

g = 9.8m/s^2

Vi = 0 m/s

I solved for the final velocity, using PEi + KEi = PEf + KEf, and found it to be 39.2 m/s. Then, I plugged that into the equation KE = 1/2mv^2, and got the Kinetic Energy, but my answer was way off. (The correct answer is 137J)

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# Kinetic Energy and bowling ball Question

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