Kinetic Energy from Velocity Vector

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SUMMARY

The kinetic energy of a 3.00 kg object moving with a velocity vector of <6,-1> m/s is calculated using the formula KE = 0.5 * m * v^2. The user correctly computes v^2 as 37, leading to a kinetic energy of 55.5 J. However, the discrepancy with the book's answer of 60.0 J suggests a potential rounding issue or a difference in significant figures. The method applied is accurate, confirming the calculation process.

PREREQUISITES
  • Understanding of kinetic energy formula (KE = 0.5 * m * v^2)
  • Familiarity with vector operations, specifically dot products
  • Basic knowledge of significant figures and rounding in physics
  • Ability to perform calculations involving mass and velocity
NEXT STEPS
  • Review vector mathematics, focusing on dot products and their applications
  • Study the principles of significant figures and rounding in scientific calculations
  • Explore kinetic energy calculations in different contexts, such as varying mass or velocity
  • Investigate common sources of error in physics problems and how to avoid them
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding kinetic energy calculations and vector mathematics.

AdkinsJr
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I just need to find the kinetic energy of a 3.00kg object moving with a velocity <6,-1> m/s. I should be able to take the dot product to find v-squared right? I find that v^2=37, multiply by 3, divide by 2, this gives 55.5 J, the book says 60.0 J. I can't figure out what the problem is.
 
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Your answer matches the correct method. Did the question ask for a certain degree of accuracy?
 
rock.freak667 said:
Your answer matches the correct method. Did the question ask for a certain degree of accuracy?

No, it just gives the velocity vector, and asks for the kinetic energy.
 

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