1. The problem statement, all variables and given/known data Point A is at a potential of +230 V, and point B is at a potential of -140 V. An -particle is a helium nucleus that contains two protons and two neutrons; the neutrons are electrically neutral. An -particle starts from rest at A and accelerates toward B. When the -particle arrives at B, what kinetic energy (in electron volts) does it have? hence: Change in potential=370 Volts 2. Relevant equations Change in potential= -work/q and 1e- moving through one volt of potential= 1.6e-19 Joules 3. The attempt at a solution He= 2 protons = 2 (1.6e-19 coulombs)= 3.2e-19c (370 Volts)(3.2e-19c)= 1.184e-16 Of course, this isn't right or I wouldn't be posting this. My ideas for where I've gone astray: -the charge (in coulombs) of He is different than 3.2e-19 -The answer asks for the kinetic energy, but I thought eV was a measure of Potential Electric Energy?