The kinetic energy of a 2kg sinker thrown vertically with an initial velocity of 10m/s from a bridge into a river 12m below is calculated using the formula KE = 1/2mv^2. The correct kinetic energy upon impact with the water is 340 Joules (3.4 x 10^2 J). This calculation considers only the initial kinetic energy and does not account for potential energy changes during the fall.
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Okay, so when the 'sinker' is thrown you've worked out that it has kinetic energy, but is that the only type of energy it has?pat666 said:Homework Statement
A 2kg sinker is thrown with a vertical velocity of 10m/s from a bridge into a river 12m below. What is the kinetic energy of the sinker when it hits the river??
Answer is 3.4*10^2 J
Homework Equations
KE = 1/2mv^2
The Attempt at a Solution
tried substituting directly into KE = 1/2mv^2 but obviously not write ant help would be appreciated.