Kinetic Energy of a flat uniform disk

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SUMMARY

The kinetic energy of a flat uniform disk with a radius of 1.5 m and mass of 10 kg rolling with a translational velocity of 12 m/s can be calculated using the equation K = 0.5(Icm)(ω)^2 + 0.5(M)(v)^2. Here, Icm represents the moment of inertia about the center of mass, which for a disk is Icm = 0.5 * M * R^2. The total kinetic energy combines both translational and rotational components, emphasizing the importance of understanding both aspects for rolling objects.

PREREQUISITES
  • Understanding of rotational dynamics and moment of inertia
  • Familiarity with the equations of motion for rolling objects
  • Knowledge of angular velocity and its relationship to linear velocity
  • Basic principles of kinetic energy in physics
NEXT STEPS
  • Calculate the moment of inertia for a flat disk using Icm = 0.5 * M * R^2
  • Learn how to derive angular velocity (ω) from translational velocity (v) for rolling objects
  • Explore the concept of total kinetic energy in rolling motion
  • Practice similar problems involving rolling objects to reinforce understanding
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of kinetic energy in rolling motion.

themilkman
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Homework Statement



A flat, uniform, disk, of radius 1.5 m and mass 10 kg, is rolling on its edge with a translational velocity of 12 m/s.
What is the kinetic energy of the disk?


Homework Equations



not sure which one but I'm guessing it's one of these two:
K = .5(I)(w)^2
K = .5(Icm)(w)^2 + .5(M)(v)^2cm

The Attempt at a Solution



I have absolutely no idea how to even start this problem, any help on what eqn to use and what I is would be extremely helpful
 
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For a rolling object - the total energy is the kinetic energy of the moving mass PLUS the rotational energy.
 

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