Kinetic energy of a spring-mass system

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SUMMARY

The total energy of a spring-mass system oscillating horizontally is 1600 J. When the displacement is one-fourth of the amplitude, the kinetic energy (KE) can be calculated using the potential energy (PE) formula, PE = 0.5kx². By substituting x with 0.25A, the equation becomes PE = 0.5k(0.25A)². The kinetic energy is then derived from the total energy as KE = total energy - PE, leading to KE = 1600 J - PE.

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  • Understanding of spring-mass systems
  • Familiarity with energy conservation principles
  • Knowledge of potential energy (PE) and kinetic energy (KE) equations
  • Basic algebra for solving equations
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  • Learn about energy transformations in mechanical systems
  • Explore the concept of amplitude in harmonic motion
  • Investigate the relationship between displacement and energy in spring-mass systems
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Homework Statement


The total energy of a spring-mass system oscillating horizontally is 1600 J. What will be the kinetic energy (in joules) of the mass when its displacement is one-fourth of its amplitude?


Homework Equations


total energy = KE + PE = .5kA2
KE = .5mv2
PE = .5kx2


The Attempt at a Solution


All I have written down is-
1600 J = .5kA2

So, I have no idea how to start solving this problem. Can anyone help me get started? Any help is appreciated!
 
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At the extreme ends of the displacement, 1/2kx^2=1600 where x is amplitude.

This leads to 1/2k (.25x)^2 = WHAT WE NEED TO KNOW. Set it up as a proportional problem.

AS the total energy is 1600J, the KE will be 1600-PE.
 

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