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What is the force needed to stop an 8,000lb tractor moving at 5mph in one foot?
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[QUOTE="Eric Ahlvin, post: 4974907, member: 538409"] I have a situation where I need to figure how much force it will take to stop an 8,000lb tractormoving at a max speed of 5mph in somewhere around a foot. It will not be an impact stop as there is nothing for it to hit but rather a heavy brake stop. It has been quite some time since I have dealt with kinetic energy equations. Can someone check my work on this? K=1/2mv^2 m=8,000lb x 0.0310809502 lbs/slug = 248.64slugs v = 5m/hr x 5280ft/mile x 1hr/60min x 1min/60sec = 7.33 ft/sec K=0.5 * 248.64slugs * 7.33^2 K= 6,680 ftlbs where F=K/d and d=1ft F= 6680Newtons and 1 Newton = 0.224808943 pounds force so F= 1501.7 lbs If someone could verify this that would be very much appreciated [/QUOTE]
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What is the force needed to stop an 8,000lb tractor moving at 5mph in one foot?
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