Kinetic energy stored in the flyweel

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SUMMARY

The kinetic energy stored in a flywheel with a radius of 2.19 m and a mass of 679 kg, rotating at 7310 revolutions per minute, is calculated using the formula KE = 1/2Iω². Initially, the user incorrectly applied the moment of inertia formula I = mr², leading to an incorrect kinetic energy calculation of 954,157,346 J. The correct moment of inertia for a solid disk is I = 1/2mr², which must be used to obtain the accurate kinetic energy value.

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Homework Statement



A car is designed to get its energy from a ro-
tating flywheel with a radius of 2.19 m and
a mass of 679 kg. Before a trip, the fly-
wheel is attached to an electric motor, which
brings the flywheel’s rotational speed up to
7310 rev/min.
Find the kinetic energy stored in the fly-
wheel.
Answer in units of J.


Homework Equations



KE = 1/2I[tex]\omega[/tex]2
I = mr2

The Attempt at a Solution



given:
r = 2.19 m
m = 679 kg
[tex]\omega[/tex] = 7310 rev/min = 765.50141 rad/s

I = mr2
= (679 kg)(2.19 m)2
= 3256.5519 kgm2

KE = 1/2I[tex]\omega[/tex]2
= 1/2(3256.5519 kgm2)(765.50141 rad/s)2
= 954157346 J

When I enter this answer, it says that it is incorrect? Could someone please let me know what I'm doing wrong?

Thank you!
 
Physics news on Phys.org
I figured it out! I was using the wrong equation for Inertia...it should be:

I = 1/2mr^2
 

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