Kinetic energy (tough algebra problem)

Click For Summary
SUMMARY

The discussion focuses on deriving an algebraic expression for the fractional loss of kinetic energy in a ballistic pendulum setup, specifically demonstrating that the ratio of kinetic energy lost to initial kinetic energy equals M/(M+m), where M represents the weight of the holder and m the weight of the metal ball. The kinetic energy formula used is 0.5mv^2. Participants emphasize the necessity of employing both conservation of momentum and conservation of energy equations to solve the problem accurately.

PREREQUISITES
  • Understanding of kinetic energy formula (0.5mv^2)
  • Knowledge of conservation of momentum principles
  • Familiarity with algebraic manipulation of equations
  • Basic concepts of collisions in physics
NEXT STEPS
  • Study the principles of conservation of momentum in collisions
  • Learn how to derive equations for kinetic energy loss in collisions
  • Explore algebraic techniques for manipulating complex equations
  • Investigate the relationship between velocity and mass in collision scenarios
USEFUL FOR

Physics students, educators, and anyone involved in experimental mechanics or ballistics who seeks to understand kinetic energy loss in collision scenarios.

captainsmith1
Messages
6
Reaction score
0

Homework Statement


Derive an algebraic statement for the fractional loss of kinetic energy in terms of symbols only and show that loss of kinetic energy/inital kinetic energy=M/(M+m)

this is for a ballistics pendulum lab, and M is the weight of the holder and m is the weight of the metal ball. The task is to prove that the ratio of the kinetic energy lost to the inital kinetic energy equals the ratio of the mass of the holder (M) to the mass of the holder and the ball together (M+m)


Homework Equations



kinetic energy (.5mv^2)

The Attempt at a Solution


i set the two ratios equal to each other, giving something that looks like this-

.5mv(initial)^2-.5(m+M)v(final)^2 = M/(m+M)
.5mv(initial)^2

but i can't figure out the algebra to prove that the two in fact do equal each other (and they do, earlier calculations in the lab prove it)
ps, sorry if the equation looks really bad, its kind of hard to type it using a keyboard
 
Physics news on Phys.org
You need more than algebra! You need some relationship between those velocities - another equation. You haven't made the problem clear, but perhaps you also have a momentum equation?
 
Hi captainsmith1! Welcome back! :wink:

Yes, you nearly always need two equations for this sort of problem …

if it's a collision, one of them will be conservation of momentum (it applies to all collisions), and the other will be conservation of energy (if it is conserved), otherwise some geometric constraint. :smile:
 

Similar threads

Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
29
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 58 ·
2
Replies
58
Views
3K
Replies
55
Views
6K
  • · Replies 6 ·
Replies
6
Views
3K