Kinetic Energy & Work Problem -- Tractor Pull Competition

Click For Summary

Homework Help Overview

The discussion revolves around a problem related to kinetic energy and work in the context of a tractor pull competition. Participants are exploring the relationship between work done, kinetic energy, and energy loss due to friction.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are attempting to relate the work done to changes in kinetic energy and questioning how to determine initial kinetic energy and energy losses due to friction. There is discussion about the equations for work and friction, as well as the implications of equal energy losses.

Discussion Status

The discussion is active, with participants providing insights into the calculations of work done by friction and its implications for energy loss. Some guidance has been offered regarding the relationship between forces and energy loss, but there is no explicit consensus on the interpretations of the problem.

Contextual Notes

Participants are navigating the complexities of the problem, including assumptions about equal energy losses and the need for additional information regarding initial kinetic energies. There is an emphasis on the role of friction in the context of the competition.

Lori

Homework Statement



upload_2017-11-6_15-11-53.png

Homework Equations



W = ΔKE
W = KEf-KEi

The Attempt at a Solution


W = .5mvf2 -.5mvi2
I know that final KE for A is 4 times the KE of B because for A ... KEf = 1/2 m (2v)^2
4KE = 1/2 m v ^2 for A

I don't know what initial KE for both of them are... so how do i know if that had equal losses of energy to friction??
 

Attachments

  • upload_2017-11-6_15-11-53.png
    upload_2017-11-6_15-11-53.png
    30.3 KB · Views: 981
Last edited by a moderator:
Physics news on Phys.org
Lori said:
so how do i know if that had equal losses of energy to friction??
How would you determine the energy loss due to friction? Hint: How would you calculate the work done by friction?
 
Hmmmm. I see where this might go. Let me see:

Wfriction = Ffriction*d
Ffriction = μk*N
N = mg --> Normal force is same for both cases

Ffrction = same for both cases

thus...! Wfriction = Ff*d (same for both blocks right cause same distance too)

Energy loss is Wfriction = energy of friction loss

I think that is it, so it proves that they loss equal amounts of friction.Also, couldn't i have found the answer by elimination? I know that b) is definitely false because there is friction and it's loss to displacement. I also know a) , d), e) is falso because I found that KE for A is 4 times B which doesn't fit for these choices... so what's left is c) --which i thought would be false, but it was proved otherwise.
 
Lori said:
I think that is it, so it proves that they loss equal amounts of friction.
Good job!

Lori said:
Also, couldn't i have found the answer by elimination?
Only if you were sure about d & e being false, which requires knowing something about the energy lost to friction.
 
  • Like
Likes   Reactions: Lori

Similar threads

  • · Replies 12 ·
Replies
12
Views
13K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 3 ·
Replies
3
Views
5K
Replies
6
Views
4K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
7
Views
2K
  • · Replies 16 ·
Replies
16
Views
1K
  • · Replies 21 ·
Replies
21
Views
5K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K