- #1
hunbogi
- 6
- 0
An Object slides with a consistent velocity down an incline that has a 30 degree angle.
I'm trying to find the kinetic friction and the ratio that the mechanical energy is lost on the way down.
I think I have already calculated µ with F(friction)= µmgcos(θ)=mgsin(θ) out comes Tan(θ) = µ
I think I did that correctly..
I'm struggling with the other part about the rate that the mechanical energy is lost. I would guess that it is not possible to get the answer in a number.
3.
I tried to us PE = mgh -friction = k2.
mgh - µmghcos(θ) = ½mv^2þ
not sure what my answer might look like in the end.
I'm trying to find the kinetic friction and the ratio that the mechanical energy is lost on the way down.
I think I have already calculated µ with F(friction)= µmgcos(θ)=mgsin(θ) out comes Tan(θ) = µ
I think I did that correctly..
I'm struggling with the other part about the rate that the mechanical energy is lost. I would guess that it is not possible to get the answer in a number.
3.
I tried to us PE = mgh -friction = k2.
mgh - µmghcos(θ) = ½mv^2þ
not sure what my answer might look like in the end.