Kinetic friction in a two mass, one pulley problem

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SUMMARY

The discussion centers on a physics problem involving two masses (m1 and m2) connected by a string over a massless pulley, where m2 is greater than m1. The participant observes that as the hanging mass (m2) increases, the coefficient of kinetic friction also appears to increase, which contradicts the established principle that kinetic friction should be independent of the mass experiencing the frictional force. The conversation highlights the need for further testing with different mass combinations to clarify the relationship between mass, acceleration, and kinetic friction.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concept of kinetic friction
  • Basic knowledge of pulley systems
  • Experience with experimental data collection and analysis
NEXT STEPS
  • Investigate the principles of kinetic friction and its independence from mass
  • Learn about the effects of surface materials on friction coefficients
  • Conduct experiments varying both m1 and m2 to observe changes in acceleration and friction
  • Explore the use of tracking software for analyzing motion in physics experiments
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of friction and pulley systems in action.

StonedPhysicist
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Homework Statement


I have solved the problem where one mass m1 is on a horizontal frictional table connected to a mass m2 which is hanging off the table by a string over a pulley (assuming pulley massless), assuming that m2 is greater than m1 there is a net acceleration causing the mass 2 to fall down and the mass 1 to follow. The problem is that the equations suggest that an increased pulling force (i.e. larger m2) causes an increased coefficient of kinetic friction, furthermore I apply this formula to the data I have and indeed a larger hanging mass gives a greater kinetic friction coefficient. Is this correct? I would have thought it should not effect the coefficient.
upload_2016-2-2_15-31-43.png


Homework Equations


upload_2016-2-2_15-31-23.png

upload_2016-2-2_15-31-32.png

upload_2016-2-2_15-31-37.png

The Attempt at a Solution


Solution already obtained, the question is about the solution.
 
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If you hold your coefficient constant, what would have to change? Is there another term that might be variable in your equation?
 
RUber said:
If you hold your coefficient constant, what would have to change? Is there another term that might be variable in your equation?
the only other variables are m2 and of course the acceleration, but using the data i have for the acceleration which was found using a camera and tracking software, i still find an increasing coefficient of kinetic friction with increasing m2
 
That is interesting. You have data for the two different masses and the acceleration terms are the same?
I would recommend running a third test -- maybe with masses that are close to each other -- clearly acceleration will need to change at some point.
 
Coefficient of friction depends on the surface on which the mass under consideration moves/undergoes relative motion
It has nothing to do with the mass of the body which experiences the frictional force!
 
RUber said:
That is interesting. You have data for the two different masses and the acceleration terms are the same?
I would recommend running a third test -- maybe with masses that are close to each other -- clearly acceleration will need to change at some point.
no, the acceleration does increase with increasing m2, but so does the kinetic friction coefficient. My understanding is that the kinetic friction should be independent of m2 and thus independent of the acceleration but this does not seem to be the case.
 
UchihaClan13 said:
Coefficient of friction depends on the surface on which the mass under consideration moves/undergoes relative motion
It has nothing to do with the mass of the body which experiences the frictional force!
i agree, but the formula and my data do not seem to suggest this, my question is why
 
Could you provide an actual picture of the data you possess??
thanks
UchihaClan13
 
UchihaClan13 said:
Could you provide an actual picture of the data you possess??
thanks
UchihaClan13
Here is the data:
upload_2016-2-2_16-20-53.png

where the paper types are what m1 is being dragged over, and 30,40 and 50g corresponds to mass m2.
 
  • #10
any more ideas?
 

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