Kinetic Friction of hockey puck

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SUMMARY

The discussion focuses on calculating the minimum initial speed required for a hockey puck to reach a teammate, given a kinetic friction coefficient (μk) of 0.1. The puck was initially given a speed of 1.71 m/s, which was insufficient to overcome the kinetic friction, causing it to travel only half the intended distance. To determine the required speed, participants are encouraged to set up equations based on either energy conservation or force analysis.

PREREQUISITES
  • Understanding of kinetic friction and its coefficient (μk)
  • Basic physics concepts of motion and forces
  • Familiarity with energy conservation principles
  • Ability to set up and solve equations in physics
NEXT STEPS
  • Calculate the minimum initial speed required using the equation of motion under friction.
  • Explore the relationship between kinetic energy and work done against friction.
  • Review examples of similar physics problems involving friction and motion.
  • Investigate the effects of different surface materials on kinetic friction coefficients.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of kinetic friction in sports contexts.

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Homework Statement



In attempting to pass the puck to a teammate, a hockey player gives it an initial speed of 1.71 m/s. However, this speed is inadequate to compensate for the kinetic friction that exists between the puck and the ice. As a result, the puck travels only one-half the distance between the players before sliding to a halt. What minimum initial speed should the puck have been given so that it just reached the teammate? Assume the force of kinetic friction is the same on the puck everywhere between the two players. Also assume the ice surface is flat and μk = 0.1.

Homework Equations





The Attempt at a Solution

 
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Have you even tried doing this problem?

Can you set up the necessary equations? Do you want to do this from an energy or force perspective? Either way works.
 

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