1. The problem statement, all variables and given/known data Given a 2.0 kg mass at rest on a horizontal surface at point zero. For 30.0 m, a constant horizontal force of 6 N is applied to the mass. For the first 15 m, the surface is frictionless. For the second 15 m, there is friction between the surface and the mass. The 6 N force continues but the mass slows to rest at the end of the 30 m. The coefficient of friction between the surface and the mass is _____. 2. Relevant equations F = ma Work-kinetic energy theorem F_friction = mu * m * g 3. The attempt at a solution To solve this, I found the velocity at 15 m by first using F=ma to find that the acceleration for the first 15 m is 3 m/s^2. Then I used a kinematic equation to find that the velocity at 15 m is sqrt(90). So then, for the second 15 m, I drew a force diagram and saw that for the mass to decelerate to 0 in the exact same distance as it took to accelerate, then the net force must be the same magnitude but in the reverse direction to slow it down. So I thought that since it was previously just 6 N to the right, I thought the force of friction would have to be 12 N to the left so that the net force is 6 N to the left. Force of friction = coeff_fric * m * g So that means that 12 = coeff_fric * m * g Solving for coeff_fric, I got 0.6. But that is apparently wrong since it's supposed to be 0.3. But the only way to get 0.3 is if Force of friction = 6 N to the left. But I don't see why it should be 6 N instead of 12 N to the left.