Kinetic Friction Problem (Truck Braking)

Click For Summary

Homework Help Overview

The problem involves a bread truck skidding to a stop due to kinetic friction, with given parameters such as initial velocity, stopping time, and the need to find the coefficient of kinetic friction.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between velocity, time, and acceleration, questioning how to derive kinetic friction from these variables. There are attempts to clarify the role of forces and the normal force in the context of Newton's laws.

Discussion Status

The discussion has progressed with participants exploring the concepts of acceleration and forces. Some have provided hints and guidance on how to relate the kinetic friction force to the normal force, leading to a clearer understanding of the problem's components.

Contextual Notes

Participants note the importance of correctly identifying the normal force and its relationship to the forces acting on the truck, while also recognizing that mass may not be necessary for the final calculation of the coefficient of kinetic friction.

Spartan Erik
Messages
29
Reaction score
0

Homework Statement



"A bread truck is traveling at 18 m/s on a horizontal road. The brakes are applied and the truck skids to a stop in 3.6s. The coefficient of kinetic friction between the tires and the road is:"

Homework Equations



Kinetic Friction = coefficient of kinetic friction x normal force

The Attempt at a Solution



I'm not sure how you can manipulate velocity and time to get kinetic friction..
 
Physics news on Phys.org
Hint: What's the truck's acceleration?
 
Well if brakes are being applied, the truck is decelerating until velocity is 0
 
Find the deceleration.
 
Well acceleration is in units of m/s^2, so 18 m/s / 3.6s = 5 m/s^2 if I'm not mistaken
 
Good! Now make use of it. Hint: What does Newton's 2nd law tell you?
 
Well F = MA, but I can't solve for force or mass.. unless of course there's something big that I'm missing..
 
Make use of what you had in your first post. The "F" is the kinetic friction force.
 
Alright so far I've established that the acceleration is 5 m/s^2, the velocity was 18 m/s, and that the time to stop was 3.6s.

Since Kinetic Friction Force = coefficient of kinetic friction x normal force

I can break the normal force into mass and acceleration, giving the equation
Kinetic Friction Force = coefficient of kinetic friction x mass x acceleration (5 m/s^2)

But I still don't see what unknowns I can solve for..
 
  • #10
The normal force does not equal "mass X acceleration". To find the normal force add up the vertical components of all forces and set it equal to zero.
 
  • #11
Oh man I feel like beating myself over the head with a stick right about now.. quite a eureka moment.

Alright so: kinetic frictional force = coefficient of k x normal force
coefficient of k = kinetic frictional force / normal force

Based off that, mass is irrelevant, so it is ultimately acceleration / gravity

So the coefficient is 0.51.. man.. thanks for spurring the ole noggin!
 
  • #12
Sweet. :wink:
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
6K
  • · Replies 4 ·
Replies
4
Views
935
Replies
7
Views
2K
Replies
18
Views
3K
  • · Replies 16 ·
Replies
16
Views
6K
Replies
19
Views
3K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 9 ·
Replies
9
Views
5K