Kinetic friction

  • Thread starter Cassie
  • Start date
  • #26
492
1
I contacted my TA about the problem. The formula was simply V^2 / 2*g*coef=s
Thank you for all your help!

yep vf^2=2as
v^2/(2a)=s
a=g*Uk
v^2/(2*g*uk)=s
 
  • #27
yes but you should've let Cassie do it or done it though pm's :s.

Also your signs are wrong, gravity (if we're going negative y is down) *.44 will give a -acceleration which opposes the motion to the right (+x side of the x axis).
and the velocity given is initial not final.

Oh oops. Alright I see
 

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